WebHow many terms of AP 54, 51, 48... are they required to give a sum of 513? (a) 21 or 25 (b) 22 or 23 (c) 23 or 24 (d) 18 or 19 Response: (d) 18 or 19 Question 3. Weba = 54, d = – 3 and S n = 513 (n 2)[2a + (n – 1) d] = 513 (n 2)[108 + (n – 1) × – 3] = 513. n 2 – 37n + 342 = 0 (n – 18) (n – 19) = 0 . n = 18 or 19. Here, the common difference is …
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Webtotally 18 terms are required to make sum as 513. 54 +51+ 48 +45 +42 + 39+ 36 +33 +30 +27 + 24 +21 +18 + 15 + 12 + 9 + 6 +3 = 513 Web5 jan. 2024 · Math Secondary School answered Find the number of terms of AP 54, 51, 48 so that the sum is 513 Advertisement Loved by our community 30 people found it helpful Frozeblood745 Answer: Step-by-step explanation: Given : a= 54 d = 51-54= -3 Sn =513 To find : n= ? Solution: Sn=n/2 [2a+ (n-1)d] 513= n/2 [2×54+ (n-1) -3] 513×2= n [108-3n+3] ship a bottle of bourbon as a gift
\"How many terms of the series \\( 54,51,48 \\). Whin be taken …
Web18 feb. 2015 · How many terms of the a.p. 48,42,36,.... be taken so that the sum is 216? How many terms of the a.p. 48,42,36,.... be taken so ... person. Raghunath Reddy. According to the given AP ,a = 48 & d = - 6 and sum of the given AP = 216. we know that S n = n/2(2a + (n -1)d) 216 = n/2(2(48) + (n -1)-6) => 432 = n(96 - 6n + 6) => 432 = 102n ... WebHow many terms of the AP: 9, 17, 25, … must be taken to give a sum of 636? ... Find the number of terms of the AP: 54, 51, 48, … so that their sum is 513. 60. In an AP, the first term is –4, the last term is 29 and the sum of all its terms is … WebFind the number of terms of the AP 54,51,48 ,. So that their sum is 513. Easy Solution Verified by Toppr Formula: S n= 2n[2a+(n−1)d] Given, 513= 2n[2(54)+(n−1)(−3)] 1026=n[108−3n+3] 3n 2−111n+1026=0 (n−19)(n−18)=0 ∴n=19,18 Was this answer helpful? 0 0 Similar questions If the sum of m terms of an AP is the same as the sum of its n terms. ship a bottle of dom perignon