WebJan 27, 2024 · If the center of the circle is at the origin (0, 0) and it passes through (0, -8) this means that the radius of the circle is 8. Because the radius is the distance from the … WebOct 10, 2024 · Because the vertices are vertically oriented, we use the general Cartesian form: (y-k)^2/a^2+(x-h)^2/b^2=1; a > b" [1]" where (h,k) is the center. The general form for vertically oriented vertices are: (h, k - a) and (h,k-a) These general forms and the given vertices (0,-5) and (0,5) allow us to write 3 equations that can be used to find the values …
Find an equation for the ellipse that has its center at the origin an…
WebJul 22, 2024 · An ellipse centered at the origin is defined by x^2/a^2 + y^2/b^2 = 1. As there is a vertex at (0, 6), b = 6. As it passes through (4, 3), then, 4^2/a^2 + 3^2/6^2 = 1 WebQuestion: Center at the origin; passes through (3,6) Center at the origin; passes through (3,6) Expert Answer. Who are the experts? Experts are tested by Chegg as specialists in their subject area. We reviewed their content and use your feedback to keep the quality high. oothapam
Solve for the equation of a circle if the center is origin …
WebQuestion: Center at the origin; passes through (3,6) Center at the origin; passes through (3,6) Expert Answer. Who are the experts? Experts are tested by Chegg as … WebFeb 23, 2024 · To ensure the point (-8,6) is contained within the circle, we must find the distance to this pint from the center, origin. You can make a right triangle with this point and the y-axis. The hypotenuse will be the … WebYou'll get a detailed solution from a subject matter expert that helps you learn core concepts. Question: Find an equation of the circle that satisfies the given conditions. (Use the variables x and y.) Center at the origin; passes through (2, 6) Find an equation of the circle that satisfies the given conditions. (Use the variables x and y .) oot gerudo theme 10 hours